How do you factor #2v ^ { 2} - 9v - 11#?
1 Answer
Aug 8, 2017
Explanation:
Given:
#2v^2-9v-11#
If you looked at this and thought "AC method", then you would be looking for a pair of factors of
If so, then they're right under your nose, namely
We can use this pair to split the middle term and factor by grouping:
#2v^2-9v-11 = (2v^2-11v)+(2v-11)#
#color(white)(2v^2-9v-11) = v(2v-11)+1(2v-11)#
#color(white)(2v^2-9v-11) = (v+1)(2v-11)#