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How do you factor #-2x ^ { 2} + 7x + 1= 0#?

1 Answer
Mar 9, 2018

Answer:

the answer is #(-7-sqrt(57))/-4# and #(-7+sqrt(57))/-4#

Explanation:

keep in mind: quadratic formula: #(-b+sqrt(b^2-4ac)/(2a))#for this, you have to use the quadratic formula
#-7sqrt((7)^2-4(-2)(1)# divide it all by #2(-2)# which is #-4# now solve the equation in the #sqrt# which would give you #-7sqrt(49+8)# then you get #-7sqrt(57)# but you still have #-4# and since it's #sqrt#, you ave negative and positive. that's how you get your answe