How do you factor #3m ^ { 2} + 10m + 8#?

1 Answer
George C.
Nov 24, 2016

#3m^2+10m+8 = (3m+4)(m+2)#

Explanation:

Given:

#3m^2+10m+8#

Use an AC method:

Find a pair of factors of #AC=3*8 = 24# with sum #B=10#.

The pair #6, 4# works.

Use this pair to split the middle term and factor by grouping:

#3m^2+10m+8 = 3m^2+6m+4m+8#

#color(white)(3m^2+10m+8) = (3m^2+6m)+(4m+8)#

#color(white)(3m^2+10m+8) = 3m(m+2)+4(m+2)#

#color(white)(3m^2+10m+8) = (3m+4)(m+2)#

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