# How do you factor #3v ^ { 2} + 12v - 63#?

##### 3 Answers

#### Explanation:

Given

First factor out the obvious constant

Then look for two numbers whose product is

With a bit of playing around you should come up with

enabling the continuation of the factoring:

#### Explanation:

Given:

#3x^2+12v-63#

First note that all of the coefficients are divisible by

#3v^2+12v-64 = 3(v^2-4v-21)#

To factor the remaining quadratic, we can find a pair of factors of

Hence we find:

#v^2-4v-21 = (v-7)(v+3)#

So:

#3x^2+12v-63 = 3(v-7)(v+3)#

#### Explanation:

First you take

Then factorise the middle:

so

and

so the final answer would be