How do you factor #3x ^ { 2} + 5x - 28= 0#?

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Answer 1 · 2017-02-04T17:18:48

#x=2 1/3# and #x=-4#

#3x^2+5x-28=0#

Factorise.

#3x^2+12x-7x-28=0#

#3x(x+4)-7(x+4)=0#

#(3x-7)(x+4)=0#

#3x-7=0# and #x+4=0#

#x=7/3=2 1/3# and #x=-4#