Question

How do you factor `40c ^ { 3} - 176c ^ { 2} + 64c`?

Answer 1

`= 8c * (5c - 2) * (c - 4)`

Explanation:

`40c^3 - 176c^2 + 64c`

`= c * (40c^2 - 176c + 64)`

`= 8c (5c^2 - 22c + 8)`

`= 8c * (5c^2 - 20c - 2c + 8)`

`= 8c * (5c (c - 4)) - (2 (c-4))`

`= 8c * (5c - 2) * (c - 4)`