How do you factor 40x ^ { 2} + 54x - 16?

1 Answer
Mar 9, 2018

2(4x-1)(5x+8)

Explanation:

Given, 40x^2+54x-16
rArr 2(20x^2+27x-8)
rArr 2(20x^2+32x-5x-8)
rArr 2[4x(5x+8)-1(5x+8)]
rArr 2(4x-1)(5x+8)