How do you factor #4u^2+9u+5# by grouping?
1 Answer
Aug 27, 2016
Explanation:
#4u^2+9u+5#
#=(4u^2+4u)+(5u+5)#
#=4u(u+1)+5(u+1)#
#=(4u+5)(u+1)#
#4u^2+9u+5#
#=(4u^2+4u)+(5u+5)#
#=4u(u+1)+5(u+1)#
#=(4u+5)(u+1)#