How do you factor #4v^2+16v+15# by grouping?

1 Answer
EZ as pi
Jul 15, 2017

#=(2v+3)(2v+5)#

Explanation:

#x^2 +16v +15#

Split the middle term into two terms using factors of #4 and 15#
#4 = 2xx2 or 1xx4" " and" "15 = 3xx5 or 1xx15#

Create common factors which will lead to common brackets.

#(4v^2 + 6v)+(10v +15)#

#=2v(2v+3)+5(2v+3)#

#=(2v+3)(2v+5)#

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