How do you factor #4y^2-11y-3#?

1 Answer
Aug 4, 2015

#4y^2-11y-3 = (4y+1)(y-3)#

Explanation:

Since #(ay+b)(cy+d) = acy^2+ (ad+bc)y + bd#

We are looking for
#color(white)("XXXX")#factors #a# and #c# of 4
#color(white)("XXXX")#and
#color(white)("XXXX")#factors #b# and #d# of #(-3)#
such that
#color(white)("XXXX")##ad + bc = -11#

Factors of 4: #{ (1,4), (2,2) }#
Factors of (-3): #{ (1,-3), (-1,3) }#

With only a few possible factor combinations the solution can be found rather quickly.,