How do you factor #5x^2-50x+120# completely?

2 Answers
Jul 20, 2017

#5(x-4)(x-6)#

Explanation:

#5x^2-50x+120#

#5(x^2-10x+24)#

#5(x-4)(x-6)#

Jul 20, 2017

See a solution process below:

Explanation:

First, we can factor a #5# out of each term in the expression:

#(5 * x^2) - (5 * 10x) + (5 * 24) =>#

#5(x^2 - 10x + 24)#

Next, we can play with pairs of factors for #24# (1 x 24; 2 x 12; 3 x 8; #color(red)(4)# x #color(blue)(6)#) which add to #10# to factor the expression within the parenthesis as:

#5(x - 4)(x - 6)#