How do you factor 6p ^ { 4} - 24p ^ { 3} - 192p ^ { 2}6p424p3192p2?

1 Answer
May 14, 2017

=6p^2(p-8)(p+4)=6p2(p8)(p+4)

Explanation:

6p^4-24p^3-192p^26p424p3192p2

=6p^2(p^2-4p-32)=6p2(p24p32)

=6p^2(p^2-8p+4p-32)=6p2(p28p+4p32)

=6p^2(p(p-8)+4(p-8))=6p2(p(p8)+4(p8))

=6p^2(p-8)(p+4)=6p2(p8)(p+4)