Question

How do you factor `6y ^ { 3} + 20y ^ { 2} + 14y`?

Answer 1

See a solution process below:

Explanation:

First, we can factor a `2y` from each term in the expression:

`(2y * 3y^2) + (2y * 10y) + (2y * 7) =>`

`2y(3y^2 + 10y + 7)`

We can now factor the expression in parenthesis as:

`2y(3y + 7)(y + 1)`