How do you factor #8s ^ { 2} - 9s + 1#?

1 Answer
smendyka
Dec 30, 2016

You need to play with the multipliers of #8# (1x8, 2x4, 4x2, 8x1) and #1# - see result below:

Explanation:

You need to play with the multipliers of #8# (1x8, 2x4, 4x2, 8x1) and #1# to factor this problem, resulting in:

#(8s - 1)(s - 1)#

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