How do you factor #-8x ^ { 2} - 28x - 24= 0#?

1 Answer
smendyka
Oct 23, 2017

We can factor this as:

#(-4x - 8)(2x + 3) = 0#

Or

#(4x + 8)(-2x - 3) = 0#

Or

#-1(4x + 8)(2x + 3) = 0#

Explanation:

See a solution process below:

We can factor this as:

#(-4x - 8)(2x + 3) = 0#

Or

#(4x + 8)(-2x - 3) = 0#

Or

#-1(4x + 8)(2x + 3) = 0#

We can also multiply each side of the original equation by #color(red)(-1)# giving:

#color(red)(-1)(-8x^2 - 28x - 24) = color(red)(-1) xx 0#

#8x^2 + 28x + 24 = 0#

Which can be factored as:

#(4x + 8)(2x + 3) = 0#

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