How do you factor #m^ { 2} + 6m + 15#?

1 Answer
iceman
Apr 2, 2017

Can not be factored using real numbers.

Explanation:

#m^2+6m+15#
Notice that the discriminant is negative:
#D=b^2-4ac#
#D=36-60=-24<0# => the roots are complex not real hence it can not be factored using real numbers.

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