How do you factor #-r ^ { 4} + 2r ^ { 3} - 6r #?

1 Answer
Feb 8, 2018

#-r(r^3-2r^2+6)#

Explanation:

You have to find the thing(s) that each term has in common with the others.

In this expression, the only thing in common is #-r# or #-1# and #r#. This means that we can factor out a #-1# and #r#:

#-r(r^3-2r^2+6)#