How do you factor #t^ { 2} - 4t - 12#?

1 Answer
Jan 3, 2017

See explanation below:

Explanation:

To factor this binomial you need to "play" with different multipliers of 12 (1x12, 2x6, 3x4, 6x2, 12x1). Additionally we know it is going to be in form:

#(t - color(red)(a))(t + color(blue)(b))#

Where:
#color(red)(a) > color(blue)(b)# because the #4t# term is negative

#color(red)(-a) + color(blue)(b) = 4#

#color(red)(a) xx color(blue)(b) = 12#

The solution is:

#(t - color(red)(6))(t + color(blue)(2))#