# How do you factor x^2+16x+48?

Apr 12, 2018

$\left(x + 12\right) \left(x + 4\right) = 0$

#### Explanation:

the form that your equations is in is
$a {x}^{2} + b x + c$
Multiply a and c (1*48) to get 48. Now, what two numbers do you multiply to get 48 and add to get 16, which is b in your equation? The answer is 4 and 12. Because they are positive, put them as factors by putting "x+" in front of each and setting them as factors in an equation that equal 0.