How do you factor #x^ { 2} + 23x = 108#?

1 Answer
Mar 26, 2018

The factored form is #(x-4)(x+27)=0#.

Explanation:

First, move everything over to one side:

#x^2+23x=108#

#x^2+23x-108=0#

Now, find two numbers that multiply to #-108# and add to #23#.

These two numbers are #27# and #-4#. Split the #x# terms into these numbers, then factor the first two terms and last two terms separately, then combine them.

Here's what that looks like:

#x^2+27x-4x-108=0#

#color(red)x(x+27)-4x-108=0#

#color(red)x(x+27)color(blue)-color(blue)4(x+27)=0#

#(color(red)xcolor(blue)-color(blue)4)(x+27)=0#

This is the factored form. Hope this helped!