How do you factor #x^ { 2} + 2x - 6= 2#?

1 Answer
smendyka
Dec 10, 2016

#(x - 2)(x + 4) = 0#

Explanation:

First, in order to factor this, we need to do the necessary math to have this quadratic equal to #0# while keeping the equation balanced:

#x^2 + 2x - 6 - 2 = 2 - 2#

#x^2 + 2x - 8 = 0#

Now, we can play with factors of #8# (1x8, 2x4, 4x2, 8x1) to find the correct factors. Additionally, one of the constants will be a plus (#+#) and one will be a minus (#-#) because of the #-8# at the end of the quadratic.

#(x - 2)(x + 4) = 0#

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