How do you factor #z^ { 2} + 17z + 52#?
1 Answer
May 14, 2017
Explanation:
Given:
#z^2+17z+52#
Find a pair of factors of
The pair
Hence:
#z^2+17z+52 = (z+13)(z+4)#
Given:
#z^2+17z+52#
Find a pair of factors of
The pair
Hence:
#z^2+17z+52 = (z+13)(z+4)#