# How do you find a_10 given 8, 3, -2,...?

Dec 6, 2016

a10=$- 37$

#### Explanation:

we have relation for Arithmetic sequence $a n = a 1 + \left(n - 1\right) d$
from given scenario
$a n = a 10$
$a 1 = 8$
$n = 10$
$d = 3 - 8 = - 5$ (difference of two terms in a way d=a(nth+1 term) --a(nth term)
therefore
$a n = a 1 + \left(n - 1\right) d$
$a 10 = 8 + \left(10 - 1\right) \left(- 5\right)$
$a 10 = 8 + \left(9\right) \left(- 5\right)$
$a 10 = 8 - 45$
$a 10 = - 37$