How do you find #a_16# given #a_n=(-1)^(n-1)[n(n-1)]#?
1 Answer
Dec 29, 2017
Explanation:
#"substitute n =16 into the nth term formula"#
#rArra_(16)=(-1)^(15)[16xx15]#
#color(white)(xxxxx)=-1xx240=-240#
