How do you find a16 given an=(−1)n−1[n(n−1)]?
1 Answer
Dec 29, 2017
Explanation:
substitute n =16 into the nth term formula
⇒a16=(−1)15[16×15]
××x=−1×240=−240
substitute n =16 into the nth term formula
⇒a16=(−1)15[16×15]
××x=−1×240=−240