Question

How do you find `a_16` given `a_n=(-1)^(n-1)[n(n-1)]`?

Answer 1

`a_(16)=-240`

Explanation:

`"substitute n =16 into the nth term formula"`

`rArra_(16)=(-1)^(15)[16xx15]`

`color(white)(xxxxx)=-1xx240=-240`