How do you find a=2b+c given b=<6,3> and c=<-4,8>?

1 Answer
Ratnaker Mehta
Jul 8, 2018

(8,14)(8,14).

Explanation:

a=2b+c=2(6,3)+(-4,8)a=2b+c=2(6,3)+(−4,8)

=(2xx6,2xx3)+(-4,8)=(2×6,2×3)+(−4,8),

=(12,6)+(-4,8)=(12,6)+(−4,8),

=(12-4,6+8)=(12−4,6+8).

rArr a=(8,14)⇒a=(8,14).

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