How do you find #a_8# given #a_n=(n!)/(2n)#? Precalculus Sequences Infinite Sequences 1 Answer Alan P. Nov 1, 2017 #a_8=color(red)(2520)# Explanation: If #a_color(blue)n=(color(blue)n!)/(2color(blue)n)# then #a_color(blue)8=(color(blue)8!)/(2 * color(blue)8)# #color(white)("XXX")=(8xx7xx6xx5xx4xx3xx2xx1)/(2xx8)# #color(white)("XXX")=7xx6xx5xx4xx3# #color(white)("XXX")=42xx5xx4xx3# #color(white)("XXX")=210xx4xx3# #color(white)("XXX")=840xx3# #color(white)("XXX")=2520# Answer link Related questions What is a sequence? How does the Fibonacci sequence relate to Pascal's triangle? What is the Fibonacci sequence? How do I find the #n#th term of the Fibonacci sequence? How do you find the general term for a sequence? How do find the #n#th term in a sequence? What is the golden ratio? How does the golden ratio relate to the Fibonacci sequence? How do you determine if -10,20,-40,80 is an arithmetic or geometric sequence? How do you determine if 15,-5,-25,-45 is an arithmetic or geometric sequence? See all questions in Infinite Sequences Impact of this question 1275 views around the world You can reuse this answer Creative Commons License