Question

How do you find a direct variation equation if y = 1/4 when x = 1/8, and how do you find x when y = 3/16?

Answer 1

A direct variation equation is of the form
`y = m*x` for some constant value `m`

We are told `(x,y) = (1/8,1/4)` is a solution to this equation so
`1/4 = m* 1/8`

`rarr m=2`

The direct variation equation is
`y=2x`

To solve for `x` when `y=3/16`
substitute `3/16` for `y` in the equation:
`3/16 = 2x`

`rarr x = 3/32`