How do you find a standard form equation for the line with point (-1,12) and is perpendicular to the line is , where 6x - 7y + 3 = 0?
When given the equation of a line in the standard form,
you obtain the standard equation form of all lines that are perpendicular by swapping A and B and change the sign of one.
Please observe that
To make the standard form of all lines that are perpendicular, swap A and B and, because B is negative, I shall change the sign of B:
To find the value of D, evaluate the standard from at the given point,
The standard form of the equation of the desired line is:
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