Question

How do you find `abs(1 + 3i)`?

Answer 1

`|1+3i| = sqrt(10)`

Explanation:

We define the modulus of a complex number `a+bi, a,b in RR`, denoted `|a+bi|`, as

`|a+bi| = sqrt(a^2+b^2)`

In this case, we have

`|1+3i| = sqrt(1^2+3^2) = sqrt(10)`