Question

How do you find `abs(1 - 5i)`?

Answer 1

`sqrt(26)`.

Explanation:

Any complex number has the form `z=a+bi`, where `a` is its real part and `b` is its imaginary part. The norm of a complex number, `z`, is defined as `|z|=sqrt(a^2+b^2)`.

In your case, the complex number `1-5i` defines `a=1` and `b=-5`. So, `a^2+b^2 = 1+25=26`