How do you find $abs( 3-2i )$ ?

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Answer 1 · 2016-06-12T06:07:52

$|3-2i| = sqrt(13)$

The modulus of a complex number $a+bi$ , denoted $|a+bi|$ , is given by

$|a+bi| = sqrt(a^2+b^2)$

and represents the distance of that number from the origin on the complex plane. Note that this is analogous to the absolute value of a real number.

For our given number, $3-2i$ , we have

$|3-2i| = sqrt(3^2+(-2)^2) = sqrt(9+4) = sqrt(13)$

How do you find abs( 3-2i )abs( 3-2i )?