Question

How do you find `abs(4-3i)`?

Answer 1

`5`

Explanation:

`|4-3i|`

for complex numbers the defn. is:

`|a+-ib|=sqrt(a^2+b^2)`

so we have:

`|4-3i|=sqrt(4^2+3^2)`

`=sqrt(16+9)=sqrt25=5`