How do you find abs( 5+12i )?

1 Answer
Aug 8, 2018

The answer is $= 13$

Explanation:

The modulus of a complex number

$z = a + i b$

is

$| z | = | a + i b | = \sqrt{{a}^{2} + {b}^{2}}$

Here, we have

$z = 5 + 12 i$

Therefore,

$| z | = \sqrt{{5}^{2} + {12}^{2}} = \sqrt{25 + 144} = \sqrt{169} = 13$