How do you find $| 5 + 12 i |$ $abs( 5+12i )$ ?

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Answer 1 · 2018-08-08T13:39:39

The answer is $= 13$ $=13$

The modulus of a complex number

$z = a + i b$ $z=a+ib$

is

$| z | = | a + i b | = \sqrt{a^{2} + b^{2}}$ $|z|= |a+ib|=sqrt(a^2+b^2)$

Here, we have

$z = 5 + 12 i$ $z=5+12i$

Therefore,

$| z | = \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = 13$ $|z|=sqrt(5^2+12^2)=sqrt(25+144)=sqrt169=13$

How do you find |5+12i|abs( 5+12i )?