# How do you find abs( 6 - 5i )?

Assuming that abs means the magnitude of the complex number we have that
$\left\mid 6 - 5 i \right\mid = \sqrt{{6}^{2} + {5}^{2}} = \sqrt{61} \approx 7.81$
Note that the norm (or magnitude) of a complex number $a + b i$
$\left\mid a + b i \right\mid = \sqrt{{a}^{2} + {b}^{2}}$
The magnitude, (or absolute value), of a complex number is the distance from the origin $\left(0 , 0\right)$ to that number in the complex plane.