How do you find $abs( 6 - 5i )$ ?

Question

2573 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-17T23:30:33

Assuming that $abs$ means the magnitude of the complex number we have that

$abs(6-5i)=sqrt(6^2+5^2)=sqrt61~~7.81$

Note that the norm (or magnitude) of a complex number $a+bi$
is

$abs(a+bi)=sqrt(a^2+b^2)$

The magnitude, (or absolute value), of a complex number is the distance from the origin $(0,0)$ to that number in the complex plane.

How do you find abs( 6 - 5i )abs( 6 - 5i )?