How do you find $abs(7- 6i )$ ?

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Answer 1 · 2016-06-16T15:18:39

$|7-6i|=sqrt(85)$

To calculate the absolute value of a complex number $z=a+bi$ you use the following formula:

$|z|=sqrt(a^2+b^2)$

For given number you get:

$|z|=sqrt(7^2+(-6)^2)=sqrt(49+36)=sqrt(85)$

How do you find abs(7- 6i )abs(7- 6i )?