Question

How do you find `abs(-8-4i)`?

Answer 1

`|-8-4i|=4sqrt5~=8.9444`.

Explanation:

For, `z=x+iy in CC, |z|=sqrt(x^2+y^2)`.

Hence, `|-8-4i|=sqrt((-8)^2+(-4)^2)=sqrt(64+16)=sqrt80=sqrt(4^2*5)=4sqrt5`.

Taking, `sqrt5~=2.2361`, Reqd. Value`~=4*2.2361=8.9444`.