How do you find #abs( 9 - 5i )#?
1 Answer
Jun 3, 2016
Explanation:
Given a complex number z = x + yi , to find the magnitude of z then
#r=|z|=|x+iy|=sqrt(x^2+y^2)# here x = 9 and y = -5
#rArrr=sqrt(9^2+(-5)^2)=sqrt106#
