# How do you find abs( 9 - 5i )?

Jun 3, 2016

$\sqrt{106}$

#### Explanation:

Given a complex number z = x + yi , to find the magnitude of z then

$r = | z | = | x + i y | = \sqrt{{x}^{2} + {y}^{2}}$

here x = 9 and y = -5

$\Rightarrow r = \sqrt{{9}^{2} + {\left(- 5\right)}^{2}} = \sqrt{106}$