# How do you find abs( i^6 )?

We know that ${i}^{2} = - 1$ hence
${i}^{6} = {\left({i}^{2}\right)}^{3} = {\left(- 1\right)}^{3} = - 1$
$\left\mid {i}^{6} \right\mid = \left\mid - 1 \right\mid = 1$