How do you find all critical point and determine the min, max and inflection given #f(x)=3x^2-4x+1#?
Critical point x=
No maxima, no inflection point.
Find f'(x) = 6x-4. Equate it to 0 to get
Now find f"(x) =6, which is a positive number (irrespective of any x) . Hence, there is a minima at x=2/3. The minima would be
Maxima does not exist.