# How do you find all local maximum and minimum points given #y=x^2-x#?

##### 1 Answer

Feb 3, 2018

See explanation.

#### Explanation:

To find the local extreme (maximum or mininmum) of a function

Here we have:

The point **can** be a critical point of

graph{2x-1 [-2.738, 2.737, -1.37, 1.367]}

As we can see the derivative changes sign from negative to positive, so the point **minimum**.

Answer:

**The function #f(x)=x^2-x# has a minimum at #x_0=1/2#. **