First, find the derivative: #f'(x)=3x^2+1#. Next, find the average rate of change of #f# over the interval #[0,2]#: #\frac{f(2)-f(0)}{2-0}=\frac{10}{2}=5#. At this point, set #f'(c)=5# and solve for #c# as follows: #3c^{2}+1=5# so #3c^{2}=4# and #c^{2}=\frac{4}{3}#. There's one value of #c# between 0 and 2 that satisfies the conclusion of the Mean Value Theorem: #c=\sqrt{4/3}=\sqrt{4}/\sqrt{3}=2/\sqrt{3}=\frac{2\sqrt{3}}{3}#.