How do you find all solutions of the differential equation #dy/dx=2y-5#?

1 Answer
bp
Jun 15, 2017

#y= C e^(2x) +5/2#

Explanation:

In this case , the variables are seperable # 1/(2y-5) dy =dx#

Or#1/2 dy/(y-5/2) =dx# Now, integrate both sides, to get

# 1/2 ln(y-5/2) = x+C1#

#ln (y-5/2)= 2x +2C1#

#y=5/2 +e^(2x +2C1)#

#y= C e^(2x) +5/2#

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