# How do you find any asymptotes of #g(x)=(2x-3)/(x^2-6x+9)#?

##### 1 Answer

Nov 1, 2016

#### Answer:

The vertical asymptote is

There is no oblique asymptote

#### Explanation:

Let's factorise the denominator

Therefore

As you cannot divide by

So

Limit

Limit

graph{(2x-3)/(x-3)^2 [-10, 10, -5, 5]}