How do you find concentration of ions? I found the Concentration of the solution now what?

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Answer 1 · 2017-11-21T18:47:19

Well, are there any data here...?

Let us suppose that you dissolved a mass of #71.02*g# of #Na_2SO_4(aq)#, a soluble salt, in a #1*L# volume of water....

And thus............... #"Concentration of sodium sulfate"="Moles of solute"/"Volume of solution"#

#[Na_2SO_4]-=((71.02*g)/(142.04*g*mol^-1))/(1*L)=0.500*mol*L^-1#

Now in SOLUTION this salt undergoes ionization to give THREE EQUIV of ions.....i.e.

#Na_2SO_4(s) stackrel(H_2O)rarr2Na^+ +SO_4^(2-)#...and given this speciation...we got....

#[Na^+]=2xx0.500*mol*L^-1=1.00*mol*L^-1#...

#[SO_4^(2-)]=1xx0.500*mol*L^-1=0.500*mol*L^-1#...

And so, you have to work out how the salt reacts in solution; to which ions does it speciate? Does this address your question?