How do you find equation of line which is perpendicular to the line #2x-3y=5# and passes through the point (2,1)?
Swap the coefficients, make one negative, and then use the point to solve for the new constant.
When given the equation of a line in the form:
It is very easy to make a line that is perpendicular to the given line:
- Swap a and b
- Change the sign of either a or b
- Make the right side an arbitrary constant, k
The two possible results are shown below:
For the given line,
Given the point
Substitute 7 for k into equation :
Equation  is the answer.