How do you find #f(-1/2)# given #f(x)=-3+4x#?

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Answer 1 · 2018-03-14T07:31:20

#-5#

#f(-1/2)=-3+4*(-1/2)=-3-2=-5#

Answer 2 · 2018-03-14T08:34:09

#f(-1/2)=-5#

#"to evaluate "f(-1/2)" substitute "x=-1/2" into "f(x)#

#f(color(red)(-1/2))=-3+(4xxcolor(red)(-1/2))#

#color(white)(xxxxxx)=-3-2=-5#