# How do you find f^-1(x) given f(x)=1/(x+2)?

Feb 16, 2017

${f}^{-} 1 \left(x\right) = \frac{1}{x} - 2$

#### Explanation:

Treat f(x) as y for now.

$y = \frac{1}{x + 2}$.

Switch x and y. So now:

$x = \frac{1}{y + 2}$

Multiply (y+2) on both sides and divide by x. You should get:

(y+2)=$\frac{1}{x}$.

Subtract 2 on both sides to get:
$y = \frac{1}{x} - 2$