How do you find #f^-1(x)# given #f(x)=1/(x+2)#?

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Answer 1 · 2017-02-16T02:02:31

#f^-1(x)=1/x-2#

Treat f(x) as y for now.

#y=1/(x+2)#.

Switch x and y. So now:

#x=1/(y+2)#

Multiply (y+2) on both sides and divide by x. You should get:

(y+2)=#1/x#.

Subtract 2 on both sides to get:
#y=1/x - 2#