How do you find #f^-1(x)# given #f(x)=-x-2#?

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Answer 1 · 2016-11-20T08:04:32

THe answer is #f^(-1)(x)=-x-2#

Let #y=-x-2#

Then, #x=-y-2#

so, #f^(-1)(x)=-x-2#

Verification,

#f(f^(-1)(x))=f(-x-2)=-(-x-2)-2#

#=x+2-2=x#

Therefore, this confirm that #f^(-1)(x)=-x-2#