# How do you find f(-8) given f(x)=x^2-3x?

$f \left(- 8\right) = 88$
$f \left(\textcolor{red}{- 8}\right) = {\left(\textcolor{red}{- 8}\right)}^{2} - 3 \left(\textcolor{red}{- 8}\right)$
$\Rightarrow f \left(- 8\right) = 64 + 24 = 88$