How do you find #f(-8)# given #f(x)=x^2-3x#?
1 Answer
Aug 25, 2016
Explanation:
To evaluate f( -8), substitute x = - 8 into f(x)
#f(color(red)(-8))=(color(red)(-8))^2-3(color(red)(-8))#
#rArrf(-8)=64+24=88#
