Question

How do you find `f(g(h(2)))` given `f(x)=2x-1` and `g(x)=3x` and `h(x)=x^2+1`?

Answer 1

29

Explanation:

Start at the bit you can do...h(2)
h(x)=`x^2+1`
h(2)=`2^2+1` =5

Next g(x)=3x
Now we are looking at g(h(2)) but we know h(2) =5
g(5) =3*5=15
So g(h(2))=15

Next f(x) =2x-1

So similarly we are looking for f(15) =2*15=29